{"id":48986,"date":"2014-01-04T15:11:42","date_gmt":"2014-01-04T13:11:42","guid":{"rendered":"http:\/\/www.sorubak.com\/blog\/?p=48986"},"modified":"2014-01-04T15:11:42","modified_gmt":"2014-01-04T13:11:42","slug":"11-sinif-fizik-dersi-1-donem-3-yazili-sorulari-2013-2014","status":"publish","type":"post","link":"https:\/\/www.sorubak.com\/blog\/11-sinif-fizik-dersi-1-donem-3-yazili-sorulari-2013-2014.html","title":{"rendered":"11.s\u0131n\u0131f fizik dersi 1.d\u00f6nem 3.yaz\u0131l\u0131 sorular\u0131 2013-2014"},"content":{"rendered":"

Yaz\u0131l\u0131n\u0131n G\u00f6rselli ve Tam Halini \u0130ndirmek \u0130\u00e7in TIKLAYINIZ<\/a><\/p>\n

TLB3 2013\/2014 1. D\u00d6NEM 3. YAZILI SINAVI SORULARI<\/p>\n

\u00a0<\/b><\/p>\n

ADI SOYADI:……………………………………………………SINIFI:…..TLB3………..NO:…………….<\/b><\/p>\n

\u00a0<\/b><\/p>\n\n\n\n
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\u015eekildeki devreye g\u00f6re:<\/p>\n

 <\/p>\n

a- Sistemin e\u015fde\u011fer s\u0131\u011fas\u0131 ka\u00e7 Farad\u2018d\u0131r?<\/p>\n

b- Ana koldan ge\u00e7en y\u00fck miktar\u0131 ka\u00e7 C dur?<\/p>\n

 <\/p>\n<\/div>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b>C2:<\/sub>4\u03bcF<\/p>\n

1-<\/b><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b>C1<\/sub>:2\u03bcF\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C3:<\/sub> 6\u03bcF\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C6<\/sub>: 4\u03bcF<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/p>\n

\u00a0<\/b><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b>\u00a0\u00a0 C4<\/sub>: 2\u03bcF<\/p>\n

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 <\/p>\n

 <\/p>\n

 <\/p>\n

V=30 V<\/p>\n

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2-Magnetik alan \u015fiddeti 2.102<\/sup> wb\/m2<\/sup> olan bir m\u0131knat\u0131s\u0131n\u00a0 kuvvet \u00e7izgileri 100cm2<\/sup> lik bir y\u00fczeyi kesince 1 wb lik ak\u0131 olu\u015fuyor. M\u0131knat\u0131s\u0131n kuvvet \u00e7izgilerinin y\u00fczey ile yapt\u0131\u011f\u0131 a\u00e7\u0131<\/b> ka\u00e7 derecedir?<\/p>\n

(cos 60=0,5 sin60=0,8 ,sin 30 =0,5 cos 30=0,8)<\/p>\n

 <\/p>\n

3-E\u011filme a\u00e7\u0131s\u0131n\u0131n 600<\/sup> oldu\u011fu bir yerde , yerin magnetik alan\u0131n\u0131n\u00a0 yatay bile\u015feni 2.10-5<\/sup> wb\/m2<\/sup> dir.Yerin magnetik alan \u015fiddeti ka\u00e7t\u0131r?(sin60=0,8,Cos 60=0,5 )<\/p>\n

 <\/p>\n

4-Magnetik alan \u015fiddeti 2.103<\/sup> wb\/m2<\/sup> olan bir m\u0131knat\u0131s\u0131n alan \u00e7izgileri bir y\u00fczeyi y\u00fczeyin normali ile 600<\/sup> lik a\u00e7\u0131 yapacak \u015fekilde kesiyor.Y\u00fczey 50 cm2<\/sup> oldu\u011funa g\u00f6re\u00a0 y\u00fczeyden ge\u00e7en magnetik ak\u0131 nedir?<\/p>\n

5-Bir b\u00f6lgede magnetik sapma a\u00e7\u0131s\u0131 kuzey-bat\u0131 ya 180<\/sup> olarak bilinmektedir.Bir u\u00e7ak pusula y\u00f6n\u00fcnde 500 km u\u00e7sa co\u011frafi kuzeyden hangi y\u00f6nde ne kadar ayr\u0131lm\u0131\u015f olur(sin18=0,308 cos18=0,951 al\u0131n\u0131z)<\/p>\n

Kuzey<\/p>\n

 <\/p>\n

Bat\u0131\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0 Do\u011fu<\/p>\n\n\n\n\n
<\/td>\n<\/tr>\n
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6-<\/p>\n\n\n\n
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\u015eekildeki devrede herbir \u00fcretecin emk\u00a0 i 1,5 volt ve i\u00e7 direnci 0,5 ohm dur.devre ak\u0131m\u0131n\u0131 hesaplay\u0131n\u0131z.<\/p>\n<\/div>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

R=2 ohm<\/p>\n\n\n\n\n
<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

 <\/p>\n

 <\/p>\n

+\u00a0\u00a0\u00a0\u00a0\u00a0 –\u00a0\u00a0\u00a0\u00a0 +\u00a0\u00a0\u00a0 –<\/p>\n

–<\/p>\n

–\u00a0\u00a0\u00a0\u00a0 +<\/p>\n\n\n\n\n
<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

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+\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 –\u00a0\u00a0 +\u00a0\u00a0\u00a0 \u00a0–<\/p>\n\n\n\n\n
<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

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7- Maddeler ba\u011f\u0131l ge\u00e7irgenliklerine g\u00f6re ka\u00e7a ayr\u0131l\u0131r. \u0130simlerini yazarak\u00a0 ba\u011f\u0131l ge\u00e7irgenlikleri\u00a0 1 den \u00e7ok b\u00fcy\u00fck olan maddelere iki \u00f6rnek veriniz.<\/p>\n

 <\/p>\n

NOT BAREM\u0130:\u00a0 \u0130lk 6 soru 15 er puan 7. soru ise 10 puan olmak \u00fczere toplam 100 puand\u0131r.<\/p>\n

\u015e\u0131kl\u0131 sorularda her \u015f\u0131k e\u015fit puan de\u011ferindedir. Ba\u015far\u0131lar\u00a0 H.Hilmi \u00e7etindede(Fizik \u00f6\u011fretmeni)<\/p>\n

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www.sorubak.com<\/a><\/p>\n

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SORULARIN AYRINTILI \u00c7\u00d6Z\u00dcMLER\u0130<\/h1>\n

1-<\/p>\n

a-<\/b>E\u015fde\u011fer s\u0131\u011fa , paralel kollar i\u00e7in:4+6+2=12 \u03bcF Bu s\u0131\u011fa di\u011ferleri ile seri ba\u011fl\u0131d\u0131r.<\/p>\n

E\u015fde\u011fer s\u0131\u011fa=1\/2 +1\/12 +1\/4 Paydalar e\u015fitlenirse\u00a0 6+1+3\/12 =10\/12 e\u015fde\u011fer s\u0131\u011fa=12\/10 \u03bcF=1,2.10-6<\/sup> F <\/b><\/p>\n

b- <\/b>Devrenin toplam y\u00fck\u00fc\u00a0\u00a0 q=Ce\u015f<\/sub> .V\u00a0\u00a0 =\u00a0 1,2.10-6<\/sup>.30=36.10-6<\/sup> C<\/b><\/p>\n

2-<\/b><\/p>\n

Ak\u0131 = B.A.cos\u03b1<\/p>\n

1\u00a0\u00a0\u00a0\u00a0 =2.102<\/sup>.10-2<\/sup> cos\u03b1(100 cm2<\/sup>=10-2<\/sup> m2<\/sup> dir )<\/p>\n

1\u00a0\u00a0\u00a0\u00a0 =2. cos\u03b1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 cos\u03b1=0,5\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u03b1=600<\/sup> bulunur. Bu a\u00e7\u0131 alan \u00e7izgilerinin y\u00fczeyin normali ile yapt\u0131\u011f\u0131 a\u00e7\u0131d\u0131r.Bize sorulan ise y\u00fczey ile yapt\u0131\u011f\u0131 a\u00e7\u0131 oldu\u011fundan\u00a0\u00a0\u00a0 \u03b2= 90-60=300<\/sup><\/b> olmal\u0131d\u0131r<\/p>\n

 <\/p>\n\n\n\n\n
<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

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\u03b2<\/p>\n

 <\/p>\n

 <\/p>\n

\u03b1<\/p>\n

3-\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/b><\/p>\n\n\n\n
\n\n\n\n
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Taral\u0131 \u00fc\u00e7genden:\u00a0 cos\u03b1=Bx<\/sub>\/B\u00a0\u00a0 cos60= Bx<\/sub>\/B<\/p>\n

\u00bd =2.10-5<\/sup>\/B\u00a0 B=4.10-5<\/sup> wb\/m2<\/sup>(yerin magnetik \u015fiddetidir)<\/p>\n<\/div>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

B<\/b>x<\/sub><\/b><\/b><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 600<\/sup><\/b><\/p>\n\n\n\n\n
<\/td>\n<\/tr>\n
<\/td>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\u00a0<\/b><\/p>\n

\u00a0<\/b><\/p>\n

 <\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 By<\/sub><\/b><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0 B<\/b><\/p>\n

\u00a0<\/b><\/p>\n

4-A=50 cm2<\/sup><\/b>=50.10-4<\/sup>m2<\/sup>=5.10-3<\/sup>m2<\/sup> olsun\u00a0 normalle yapt\u0131\u011f\u0131 a\u00e7\u0131 ise 600<\/sup> oldu\u011fundan:<\/p>\n

Ak\u0131=<\/b>B:A:Cos600<\/sup> =2.103<\/sup>.5.10-3<\/sup>. Cos600<\/sup>=10.1\/2=5 wb bulunur.<\/p>\n\n\n\n
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Sin18=X\/500\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 0,308=X\/500\u00a0\u00a0 X=154 km Bat\u0131 y\u00f6n\u00fcne ayr\u0131lm\u0131\u015ft\u0131r.<\/p>\n<\/div>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

5-\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 co\u011f.kuzey<\/b><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 500m\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0<\/b>180<\/sup><\/b><\/p>\n

6- 4 <\/b>\u00a0\u00fcretecin emk\u00a0 i 3 V bulunur.\u00c7\u00fcnk\u00fc \u00fcst kol 3 v alt kol 3v kollar paralel oldu\u011fundan d\u00f6rd\u00fc 3V eder.\u00a0 5. \u00fcrete\u00e7 ise z\u0131t y\u00f6nde ak\u0131m veriyor. Devrenin toplam emk i\u00a0 3-1,5 =1,5 V olur.\u00dcst koldaki iki \u00fcretecin i\u00e7 direnci 0,5 + 0,5 =1 ohm\u00a0 Alt kolda 1 ohm\u00a0 oldu\u011fundan paralel kollar\u0131n toplam direnci<\/p>\n

1\/1+1\/1 den paydalar e\u015fitlendi\u011finde denk diren\u00e7 0,5 ohm bulunur.<\/b><\/p>\n

5 \u00fcretecin\u00a0 i\u00e7 diren\u00e7 toplam\u0131 :0,5+0,5 =1 ohm\u00a0 devre ak\u0131m\u0131 ise:\u00a0\u00a0 I= 1,5\/2+1 =0,5 A bulunur<\/b><\/p>\n

7-<\/b>\u00dc\u00e7e ayr\u0131l\u0131r: 1-Diyamagnetik maddeler 2-paramagnetik maddeler 3-ferromagnetik maddeler<\/p>\n

Ba\u011f\u0131l ge\u00e7irgenli\u011fi 1 den \u00e7ok b\u00fcy\u00fck olan maddelere \u00f6rnekler:<\/b>Demir,Nikel.Kobalt,yumu\u015fak \u00e7elik,permalloy, demir-nikel-mangan ala\u015f\u0131m\u0131\u00a0 gibi maddelerdir<\/p>\n

Dok\u00fcman\u0131n Tam Halini \u0130ndirmek \u0130\u00e7in TIKLAYINIZ<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

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