{"id":3204,"date":"2011-11-12T12:16:10","date_gmt":"2011-11-12T10:16:10","guid":{"rendered":"http:\/\/www.sorubak.com\/blog\/?p=3204"},"modified":"2011-11-12T12:16:10","modified_gmt":"2011-11-12T10:16:10","slug":"fiziko-kimya-termodinamik-gibbs-serbest-enerji","status":"publish","type":"post","link":"https:\/\/www.sorubak.com\/blog\/fiziko-kimya-termodinamik-gibbs-serbest-enerji.html","title":{"rendered":"Fiziko Kimya &#8211; Termodinamik &#8211; Gibbs Serbest Enerji"},"content":{"rendered":"<p>Baz\u0131 reaksiyonlar \u00e7evreye \u0131s\u0131 yay\u0131yordur ve <span style=\"font-family: Symbol;\">D<\/span><em>H<\/em><br \/>\n&lt; 0 oldu\u011fundan reaksiyon kendili\u011finden olu\u015fur yani istemlidir. Ba\u015fka bir<br \/>\nraeaksiyon ise sistemin d\u00fczensizli\u011finin artmas\u0131 nedeniyle <span style=\"font-family: Symbol;\">D<\/span><em>S<\/em> &gt; 0 oluyor ve yine reaksiyon kendili\u011finden<br \/>\nger\u00e7ekle\u015fiyor. Bu olaylar\u0131 tam olarak a\u00e7\u0131klayabilmek aralar\u0131nda bir ba\u011flant\u0131<br \/>\nkurabilmek i\u00e7in yeni bir terime ihtiyam\u0131z vard\u0131r. Buda gibbs serbest enerjisidir<br \/>\nve G i\u015fareti ile tan\u0131mlan\u0131r.<br \/>\nDaha \u00f6nce \u00f6\u011frendi\u011fimiz form\u00fclleri bir kere daha<br \/>\ng\u00f6zden ge\u00e7irecek olursak Sabit bas\u0131n\u00e7 alt\u0131nda bir reaksiyonun olu\u015fumu s\u0131ras\u0131nda<br \/>\n\u0131s\u0131 de\u011fi\u015fimi entalpi de\u011fi\u015fimine e\u015fittir.<br \/>\nqp=<span style=\"font-family: Symbol;\">D<\/span><em>H<\/em>\u00e7evre<br \/>\nSabit bas\u0131n\u00e7 ve s\u0131cakl\u0131k alt\u0131nda <span style=\"font-family: Symbol;\">D<\/span>S\u00e7evre a\u015fa\u011f\u0131daki form\u00fcl ile hesaplan\u0131yordu. Buradaki <span style=\"font-family: Symbol;\">D<\/span>H reaksiyonun entalpi de\u011fi\u015fimi, T ise mutlak<br \/>\ns\u0131cakl\u0131k<br \/>\n<span style=\"font-family: Symbol;\">D<\/span>S\u00e7evre = &#8211; <span style=\"font-family: Symbol;\">D<\/span>H\/T<br \/>\nToplam entropi de\u011fi\u015fimi<\/p>\n<p><span style=\"font-family: Symbol;\">D<\/span>Stoplam = <span style=\"font-family: Symbol;\">D<\/span>S sistem + <span style=\"font-family: Symbol;\">D<\/span>S\u00e7evre<br \/>\n<span style=\"font-family: Symbol;\">D<\/span>Stoplam = <span style=\"font-family: Symbol;\">D<\/span>S sistem &#8211; <span style=\"font-family: Symbol;\">D<\/span>H\/T e\u015fitli\u011fin her iki<br \/>\ntaraf\u0131 (-T) ile \u00e7arp\u0131l\u0131rsa<\/p>\n<p><span style=\"color: navy;\">-T<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">Stoplam =<br \/>\n<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">H &#8211;<br \/>\nT<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">S<\/span> ba\u011f\u0131nt\u0131s\u0131 elde edilir ve bu ba\u011f\u0131nt\u0131 gibbs serbest enerjisi<br \/>\nile bir reaksiyonun kendili\u011finden olup olu\u015fmayaca\u011f\u0131n\u0131 a\u00e7\u0131klamak amac\u0131 ile<br \/>\nkullan\u0131l\u0131r.<\/p>\n<p>Serbest enerji<\/p>\n<p><span style=\"color: navy;\">G = H-TS<\/span><br \/>\nifadesi ile tan\u0131mlan\u0131r.<\/p>\n<p>Sabit bas\u0131n\u00e7 ve s\u0131cakl\u0131kta reaksiyonun serbest<br \/>\nenerji de\u011fi\u015fimi<br \/>\n<strong><span style=\"color: red;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: red;\">G = <\/span><span style=\"color: red;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: red;\">H &#8211; T<\/span><span style=\"color: red;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: red;\">S <\/span><\/strong>olarak tan\u0131mlan\u0131r.<\/p>\n<p><span style=\"color: navy;\">-T<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">Stoplam =<br \/>\n<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">H &#8211;<br \/>\nT<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">S<\/span><br \/>\n<span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">G = -T<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">Stoplam <\/span>\u015feklinde ba\u011flant\u0131 kurulabilir. Peki ne anlama<br \/>\ngelmektedir bu form\u00fcller .<\/p>\n<p>Bunu da \u015f\u00f6yle \u00f6zetliyebiliriz.<\/p>\n<ul>\n<li>Kendili\u011finden olan de\u011fi\u015fimlerde sistemin serbest enerjisi azal\u0131r.<\/li>\n<\/ul>\n<p><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">Stoplam <\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&gt;<\/span><\/span><span style=\"color: navy;\"> 0 <\/span>olaca\u011f\u0131ndan<span style=\"color: navy;\"> &#8211; T<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">S<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&lt;<\/span><\/span><span style=\"color: navy;\"> 0 olacakt\u0131r. <\/span><br \/>\nB\u00f6ylelikle sabit bas\u0131n\u00e7 ve s\u0131cakl\u0131k alt\u0131nda<br \/>\n<span style=\"color: navy;\">&#8211; T<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">S<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&lt;<\/span><\/span><span style=\"color: navy;\"> 0 <\/span>oldu\u011fundan <span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">G<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&lt;<\/span><\/span><span style=\"color: navy;\"> 0<br \/>\n<\/span>olacakt\u0131r.<br \/>\n<span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">G negatif ise reaksiyon kendili\u011finden olu\u015fur.<\/span><\/p>\n<ul>\n<li>Dengede bir sistemde <span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">Stoplam =0 olaca\u011f\u0131ndan , &#8211; T<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">S = 0 ve <\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">G = 0<br \/>\n<\/span>olacakt\u0131r.<\/li>\n<\/ul>\n<p><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">G = 0 sistem dengededir. <\/span><\/p>\n<ul>\n<li><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">D<\/span><\/span><span style=\"color: navy;\">G<br \/>\n<\/span><span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&gt;<\/span><\/span><span style=\"color: navy;\"> 0<br \/>\nise reaksiyon kendili\u011finden olu\u015fmaz.<\/span><\/li>\n<\/ul>\n<p>\u00d6zetle bir reaksiyonun<br \/>\nkendili\u011finden olabilmesi i\u00e7in <span style=\"font-family: Symbol;\">D<\/span>G\ufffd nin negatif olmas\u0131<br \/>\ngerekmektedir. Buda <span style=\"font-family: Symbol;\">D<\/span>H <span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&lt;<\/span><\/span><span style=\"color: navy;\"> 0 <\/span>veya <span style=\"font-family: Symbol;\">D<\/span>S<span style=\"color: navy;\"><span style=\"font-family: Symbol;\">&gt;<\/span><\/span><span style=\"color: navy;\"> 0 <\/span>olmas\u0131 ile sa\u011flanabilir.<\/p>\n<p><span style=\"color: navy;\">Hesaplama<br \/>\nyaparken bile\u015fiklerin standart serbest olu\u015fum enerjisi ( <\/span><span style=\"font-family: Symbol;\">D<\/span>G\u00ba) hesaplan\u0131rken<br \/>\n<span style=\"font-family: Symbol;\">D<\/span>G\u00ba = (<span style=\"font-family: Symbol;\">D<\/span>G\u00ba\u00fcr\u00fcnler &#8211; <span style=\"font-family: Symbol;\">D<\/span>G\u00ba reaktantlar )<br \/>\n\u015feklinde hesaplanabilir. Burada dikkat edilmesi gereken \u015fey <strong>elementlerin<br \/>\n<\/strong>(O2, N2 gibi) standart serbest olu\u015fum entalpiler <strong>0<\/strong>\ufffdd\u0131r<\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Baz\u0131 reaksiyonlar \u00e7evreye \u0131s\u0131 yay\u0131yordur ve DH &lt; 0 oldu\u011fundan reaksiyon kendili\u011finden olu\u015fur yani istemlidir. Ba\u015fka bir raeaksiyon ise sistemin d\u00fczensizli\u011finin artmas\u0131 nedeniyle DS &gt; 0 oluyor ve yine reaksiyon kendili\u011finden ger\u00e7ekle\u015fiyor. Bu olaylar\u0131 tam olarak a\u00e7\u0131klayabilmek aralar\u0131nda bir ba\u011flant\u0131 kurabilmek i\u00e7in yeni bir terime ihtiyam\u0131z vard\u0131r. Buda gibbs serbest enerjisidir ve G i\u015fareti ile &#8230; <a title=\"Fiziko Kimya &#8211; Termodinamik &#8211; Gibbs Serbest Enerji\" class=\"read-more\" href=\"https:\/\/www.sorubak.com\/blog\/fiziko-kimya-termodinamik-gibbs-serbest-enerji.html\" aria-label=\"More on Fiziko Kimya &#8211; Termodinamik &#8211; Gibbs Serbest Enerji\">Devam\u0131n\u0131 oku&#8230;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[7,15],"tags":[999,1000],"class_list":["post-3204","post","type-post","status-publish","format-standard","hentry","category-dn","category-fen-teknoloji","tag-fiziko-kimya","tag-gibbs-serbest-enerji"],"_links":{"self":[{"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/posts\/3204","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/comments?post=3204"}],"version-history":[{"count":0,"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/posts\/3204\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/media?parent=3204"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/categories?post=3204"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.sorubak.com\/blog\/wp-json\/wp\/v2\/tags?post=3204"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}